High Voltage Circuit Breakers: Design and Applications by Ruben D. Garzon

By Ruben D. Garzon

Presents details on circuit breakers from the most typical layout info, functions and strategies to gear choice, specification and checking out. The textual content methods method basics and mechanical and electric engineering ideas from a simplified qualitative standpoint. It evaluates and compares the yankee nationwide criteria Institute (ANSI) and the foreign Electrotechnical fee (IEC) criteria.

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4 Mayr's Theory Mayr took a radically different approach to that of Cassie, and in 1943 he published his theory [6]. He considered an arc column where the arc diameter is constant and where the arc temperature varies as a function of time, and of the radial dimension. He further assumed that the decay of the temperature of the arc was due to thermal conduction and that the electrical conductivity of the arc was dependent on temperature. From an analysis of the thermal conduction in Nitrogen at 6000 Kelvin and below, Mayr found only a slow increase of heat loss rate in relation with the axial temperature; therefore he assumed a constant power loss No which is independent of temperature or current.

11. lJ. C. Ludwig, A simple model for high current arcs stabilized by forced convection, Journal Applied Physics 46: 3352-3360, 1975. 12. B. W. Swanson and R. M. Roidt, Numerical solutions for an SF6 arc, Proceedings IEEE 59: 493-501, 1971. 13. G. A Rich, Recovery Speed of an Axial Flow Gas Blast Interrupter, IEEE Transactions Pow. App. Syst. -93, 1675, 1974. 14. T. Tuma and lJ. Lowke, Prediction of Properties of arcs stabilized by forced convection, J. Appl. Phys. 46: 3361-3367, 1975. The Fundamentals ofElectric Arcs 27 15.

Calculate the normal, or rated current at the rated voltage, at the point of the fault corresponding to the chosen base KVA. I _ (KVA)b x 1000 n- 5. Calculate the per unit short circuit current corresponding to the per unit system voltage divided by the per unit total reactance. I pu 6. 3xv =_E_=_1_ XpJtotal) Calculate the fault current magnitude by multiplying the per unit current (Ip ,) times the rated current (I,). The following example is given to illustrate the application of the per unit method to the solution of a short circuit problem.

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